(2x+5)(3x^2-4x+1)=

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Solution for (2x+5)(3x^2-4x+1)= equation: 


Simplifying
(2x + 5)(3x2 + -4x + 1) = 0

Reorder the terms:
(5 + 2x)(3x2 + -4x + 1) = 0

Reorder the terms:
(5 + 2x)(1 + -4x + 3x2) = 0

Multiply (5 + 2x) * (1 + -4x + 3x2)
(5(1 + -4x + 3x2) + 2x * (1 + -4x + 3x2)) = 0
((1 * 5 + -4x * 5 + 3x2 * 5) + 2x * (1 + -4x + 3x2)) = 0
((5 + -20x + 15x2) + 2x * (1 + -4x + 3x2)) = 0
(5 + -20x + 15x2 + (1 * 2x + -4x * 2x + 3x2 * 2x)) = 0
(5 + -20x + 15x2 + (2x + -8x2 + 6x3)) = 0

Reorder the terms:
(5 + -20x + 2x + 15x2 + -8x2 + 6x3) = 0

Combine like terms: -20x + 2x = -18x
(5 + -18x + 15x2 + -8x2 + 6x3) = 0

Combine like terms: 15x2 + -8x2 = 7x2
(5 + -18x + 7x2 + 6x3) = 0

Solving
5 + -18x + 7x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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